Integrand size = 39, antiderivative size = 295 \[ \int (d+e x)^{7/2} \sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2} \, dx=\frac {256 \left (c d^2-a e^2\right )^4 \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{3/2}}{3465 c^5 d^5 (d+e x)^{3/2}}+\frac {128 \left (c d^2-a e^2\right )^3 \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{3/2}}{1155 c^4 d^4 \sqrt {d+e x}}+\frac {32 \left (c d^2-a e^2\right )^2 \sqrt {d+e x} \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{3/2}}{231 c^3 d^3}+\frac {16 \left (c d^2-a e^2\right ) (d+e x)^{3/2} \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{3/2}}{99 c^2 d^2}+\frac {2 (d+e x)^{5/2} \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{3/2}}{11 c d} \]
256/3465*(-a*e^2+c*d^2)^4*(a*d*e+(a*e^2+c*d^2)*x+c*d*e*x^2)^(3/2)/c^5/d^5/ (e*x+d)^(3/2)+16/99*(-a*e^2+c*d^2)*(e*x+d)^(3/2)*(a*d*e+(a*e^2+c*d^2)*x+c* d*e*x^2)^(3/2)/c^2/d^2+2/11*(e*x+d)^(5/2)*(a*d*e+(a*e^2+c*d^2)*x+c*d*e*x^2 )^(3/2)/c/d+128/1155*(-a*e^2+c*d^2)^3*(a*d*e+(a*e^2+c*d^2)*x+c*d*e*x^2)^(3 /2)/c^4/d^4/(e*x+d)^(1/2)+32/231*(-a*e^2+c*d^2)^2*(a*d*e+(a*e^2+c*d^2)*x+c *d*e*x^2)^(3/2)*(e*x+d)^(1/2)/c^3/d^3
Time = 0.12 (sec) , antiderivative size = 187, normalized size of antiderivative = 0.63 \[ \int (d+e x)^{7/2} \sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2} \, dx=\frac {2 ((a e+c d x) (d+e x))^{3/2} \left (128 a^4 e^8-64 a^3 c d e^6 (11 d+3 e x)+48 a^2 c^2 d^2 e^4 \left (33 d^2+22 d e x+5 e^2 x^2\right )-8 a c^3 d^3 e^2 \left (231 d^3+297 d^2 e x+165 d e^2 x^2+35 e^3 x^3\right )+c^4 d^4 \left (1155 d^4+2772 d^3 e x+2970 d^2 e^2 x^2+1540 d e^3 x^3+315 e^4 x^4\right )\right )}{3465 c^5 d^5 (d+e x)^{3/2}} \]
(2*((a*e + c*d*x)*(d + e*x))^(3/2)*(128*a^4*e^8 - 64*a^3*c*d*e^6*(11*d + 3 *e*x) + 48*a^2*c^2*d^2*e^4*(33*d^2 + 22*d*e*x + 5*e^2*x^2) - 8*a*c^3*d^3*e ^2*(231*d^3 + 297*d^2*e*x + 165*d*e^2*x^2 + 35*e^3*x^3) + c^4*d^4*(1155*d^ 4 + 2772*d^3*e*x + 2970*d^2*e^2*x^2 + 1540*d*e^3*x^3 + 315*e^4*x^4)))/(346 5*c^5*d^5*(d + e*x)^(3/2))
Time = 0.47 (sec) , antiderivative size = 317, normalized size of antiderivative = 1.07, number of steps used = 5, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.128, Rules used = {1128, 1128, 1128, 1128, 1122}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int (d+e x)^{7/2} \sqrt {x \left (a e^2+c d^2\right )+a d e+c d e x^2} \, dx\) |
\(\Big \downarrow \) 1128 |
\(\displaystyle \frac {8 \left (d^2-\frac {a e^2}{c}\right ) \int (d+e x)^{5/2} \sqrt {c d e x^2+\left (c d^2+a e^2\right ) x+a d e}dx}{11 d}+\frac {2 (d+e x)^{5/2} \left (x \left (a e^2+c d^2\right )+a d e+c d e x^2\right )^{3/2}}{11 c d}\) |
\(\Big \downarrow \) 1128 |
\(\displaystyle \frac {8 \left (d^2-\frac {a e^2}{c}\right ) \left (\frac {2 \left (d^2-\frac {a e^2}{c}\right ) \int (d+e x)^{3/2} \sqrt {c d e x^2+\left (c d^2+a e^2\right ) x+a d e}dx}{3 d}+\frac {2 (d+e x)^{3/2} \left (x \left (a e^2+c d^2\right )+a d e+c d e x^2\right )^{3/2}}{9 c d}\right )}{11 d}+\frac {2 (d+e x)^{5/2} \left (x \left (a e^2+c d^2\right )+a d e+c d e x^2\right )^{3/2}}{11 c d}\) |
\(\Big \downarrow \) 1128 |
\(\displaystyle \frac {8 \left (d^2-\frac {a e^2}{c}\right ) \left (\frac {2 \left (d^2-\frac {a e^2}{c}\right ) \left (\frac {4 \left (d^2-\frac {a e^2}{c}\right ) \int \sqrt {d+e x} \sqrt {c d e x^2+\left (c d^2+a e^2\right ) x+a d e}dx}{7 d}+\frac {2 \sqrt {d+e x} \left (x \left (a e^2+c d^2\right )+a d e+c d e x^2\right )^{3/2}}{7 c d}\right )}{3 d}+\frac {2 (d+e x)^{3/2} \left (x \left (a e^2+c d^2\right )+a d e+c d e x^2\right )^{3/2}}{9 c d}\right )}{11 d}+\frac {2 (d+e x)^{5/2} \left (x \left (a e^2+c d^2\right )+a d e+c d e x^2\right )^{3/2}}{11 c d}\) |
\(\Big \downarrow \) 1128 |
\(\displaystyle \frac {8 \left (d^2-\frac {a e^2}{c}\right ) \left (\frac {2 \left (d^2-\frac {a e^2}{c}\right ) \left (\frac {4 \left (d^2-\frac {a e^2}{c}\right ) \left (\frac {2 \left (d^2-\frac {a e^2}{c}\right ) \int \frac {\sqrt {c d e x^2+\left (c d^2+a e^2\right ) x+a d e}}{\sqrt {d+e x}}dx}{5 d}+\frac {2 \left (x \left (a e^2+c d^2\right )+a d e+c d e x^2\right )^{3/2}}{5 c d \sqrt {d+e x}}\right )}{7 d}+\frac {2 \sqrt {d+e x} \left (x \left (a e^2+c d^2\right )+a d e+c d e x^2\right )^{3/2}}{7 c d}\right )}{3 d}+\frac {2 (d+e x)^{3/2} \left (x \left (a e^2+c d^2\right )+a d e+c d e x^2\right )^{3/2}}{9 c d}\right )}{11 d}+\frac {2 (d+e x)^{5/2} \left (x \left (a e^2+c d^2\right )+a d e+c d e x^2\right )^{3/2}}{11 c d}\) |
\(\Big \downarrow \) 1122 |
\(\displaystyle \frac {2 (d+e x)^{5/2} \left (x \left (a e^2+c d^2\right )+a d e+c d e x^2\right )^{3/2}}{11 c d}+\frac {8 \left (d^2-\frac {a e^2}{c}\right ) \left (\frac {2 (d+e x)^{3/2} \left (x \left (a e^2+c d^2\right )+a d e+c d e x^2\right )^{3/2}}{9 c d}+\frac {2 \left (d^2-\frac {a e^2}{c}\right ) \left (\frac {2 \sqrt {d+e x} \left (x \left (a e^2+c d^2\right )+a d e+c d e x^2\right )^{3/2}}{7 c d}+\frac {4 \left (d^2-\frac {a e^2}{c}\right ) \left (\frac {2 \left (x \left (a e^2+c d^2\right )+a d e+c d e x^2\right )^{3/2}}{5 c d \sqrt {d+e x}}+\frac {4 \left (d^2-\frac {a e^2}{c}\right ) \left (x \left (a e^2+c d^2\right )+a d e+c d e x^2\right )^{3/2}}{15 c d^2 (d+e x)^{3/2}}\right )}{7 d}\right )}{3 d}\right )}{11 d}\) |
(2*(d + e*x)^(5/2)*(a*d*e + (c*d^2 + a*e^2)*x + c*d*e*x^2)^(3/2))/(11*c*d) + (8*(d^2 - (a*e^2)/c)*((2*(d + e*x)^(3/2)*(a*d*e + (c*d^2 + a*e^2)*x + c *d*e*x^2)^(3/2))/(9*c*d) + (2*(d^2 - (a*e^2)/c)*((2*Sqrt[d + e*x]*(a*d*e + (c*d^2 + a*e^2)*x + c*d*e*x^2)^(3/2))/(7*c*d) + (4*(d^2 - (a*e^2)/c)*((4* (d^2 - (a*e^2)/c)*(a*d*e + (c*d^2 + a*e^2)*x + c*d*e*x^2)^(3/2))/(15*c*d^2 *(d + e*x)^(3/2)) + (2*(a*d*e + (c*d^2 + a*e^2)*x + c*d*e*x^2)^(3/2))/(5*c *d*Sqrt[d + e*x])))/(7*d)))/(3*d)))/(11*d)
3.21.27.3.1 Defintions of rubi rules used
Int[((d_.) + (e_.)*(x_))^(m_)*((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(p_), x_S ymbol] :> Simp[e*(d + e*x)^(m - 1)*((a + b*x + c*x^2)^(p + 1)/(c*(p + 1))), x] /; FreeQ[{a, b, c, d, e, m, p}, x] && EqQ[c*d^2 - b*d*e + a*e^2, 0] && EqQ[m + p, 0]
Int[((d_.) + (e_.)*(x_))^(m_)*((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(p_), x_S ymbol] :> Simp[e*(d + e*x)^(m - 1)*((a + b*x + c*x^2)^(p + 1)/(c*(m + 2*p + 1))), x] + Simp[Simplify[m + p]*((2*c*d - b*e)/(c*(m + 2*p + 1))) Int[(d + e*x)^(m - 1)*(a + b*x + c*x^2)^p, x], x] /; FreeQ[{a, b, c, d, e, m, p}, x] && EqQ[c*d^2 - b*d*e + a*e^2, 0] && IGtQ[Simplify[m + p], 0]
Time = 2.90 (sec) , antiderivative size = 233, normalized size of antiderivative = 0.79
method | result | size |
default | \(\frac {2 \left (c d x +a e \right ) \left (315 c^{4} d^{4} e^{4} x^{4}-280 a \,c^{3} d^{3} e^{5} x^{3}+1540 c^{4} d^{5} e^{3} x^{3}+240 a^{2} c^{2} d^{2} e^{6} x^{2}-1320 a \,c^{3} d^{4} e^{4} x^{2}+2970 c^{4} d^{6} e^{2} x^{2}-192 a^{3} c d \,e^{7} x +1056 a^{2} c^{2} d^{3} e^{5} x -2376 a \,c^{3} d^{5} e^{3} x +2772 c^{4} d^{7} e x +128 a^{4} e^{8}-704 a^{3} c \,d^{2} e^{6}+1584 a^{2} c^{2} d^{4} e^{4}-1848 a \,c^{3} d^{6} e^{2}+1155 c^{4} d^{8}\right ) \sqrt {\left (c d x +a e \right ) \left (e x +d \right )}}{3465 c^{5} d^{5} \sqrt {e x +d}}\) | \(233\) |
gosper | \(\frac {2 \left (c d x +a e \right ) \left (315 c^{4} d^{4} e^{4} x^{4}-280 a \,c^{3} d^{3} e^{5} x^{3}+1540 c^{4} d^{5} e^{3} x^{3}+240 a^{2} c^{2} d^{2} e^{6} x^{2}-1320 a \,c^{3} d^{4} e^{4} x^{2}+2970 c^{4} d^{6} e^{2} x^{2}-192 a^{3} c d \,e^{7} x +1056 a^{2} c^{2} d^{3} e^{5} x -2376 a \,c^{3} d^{5} e^{3} x +2772 c^{4} d^{7} e x +128 a^{4} e^{8}-704 a^{3} c \,d^{2} e^{6}+1584 a^{2} c^{2} d^{4} e^{4}-1848 a \,c^{3} d^{6} e^{2}+1155 c^{4} d^{8}\right ) \sqrt {c d e \,x^{2}+a \,e^{2} x +c \,d^{2} x +a d e}}{3465 c^{5} d^{5} \sqrt {e x +d}}\) | \(243\) |
2/3465*(c*d*x+a*e)*(315*c^4*d^4*e^4*x^4-280*a*c^3*d^3*e^5*x^3+1540*c^4*d^5 *e^3*x^3+240*a^2*c^2*d^2*e^6*x^2-1320*a*c^3*d^4*e^4*x^2+2970*c^4*d^6*e^2*x ^2-192*a^3*c*d*e^7*x+1056*a^2*c^2*d^3*e^5*x-2376*a*c^3*d^5*e^3*x+2772*c^4* d^7*e*x+128*a^4*e^8-704*a^3*c*d^2*e^6+1584*a^2*c^2*d^4*e^4-1848*a*c^3*d^6* e^2+1155*c^4*d^8)*((c*d*x+a*e)*(e*x+d))^(1/2)/c^5/d^5/(e*x+d)^(1/2)
Time = 0.46 (sec) , antiderivative size = 315, normalized size of antiderivative = 1.07 \[ \int (d+e x)^{7/2} \sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2} \, dx=\frac {2 \, {\left (315 \, c^{5} d^{5} e^{4} x^{5} + 1155 \, a c^{4} d^{8} e - 1848 \, a^{2} c^{3} d^{6} e^{3} + 1584 \, a^{3} c^{2} d^{4} e^{5} - 704 \, a^{4} c d^{2} e^{7} + 128 \, a^{5} e^{9} + 35 \, {\left (44 \, c^{5} d^{6} e^{3} + a c^{4} d^{4} e^{5}\right )} x^{4} + 10 \, {\left (297 \, c^{5} d^{7} e^{2} + 22 \, a c^{4} d^{5} e^{4} - 4 \, a^{2} c^{3} d^{3} e^{6}\right )} x^{3} + 6 \, {\left (462 \, c^{5} d^{8} e + 99 \, a c^{4} d^{6} e^{3} - 44 \, a^{2} c^{3} d^{4} e^{5} + 8 \, a^{3} c^{2} d^{2} e^{7}\right )} x^{2} + {\left (1155 \, c^{5} d^{9} + 924 \, a c^{4} d^{7} e^{2} - 792 \, a^{2} c^{3} d^{5} e^{4} + 352 \, a^{3} c^{2} d^{3} e^{6} - 64 \, a^{4} c d e^{8}\right )} x\right )} \sqrt {c d e x^{2} + a d e + {\left (c d^{2} + a e^{2}\right )} x} \sqrt {e x + d}}{3465 \, {\left (c^{5} d^{5} e x + c^{5} d^{6}\right )}} \]
2/3465*(315*c^5*d^5*e^4*x^5 + 1155*a*c^4*d^8*e - 1848*a^2*c^3*d^6*e^3 + 15 84*a^3*c^2*d^4*e^5 - 704*a^4*c*d^2*e^7 + 128*a^5*e^9 + 35*(44*c^5*d^6*e^3 + a*c^4*d^4*e^5)*x^4 + 10*(297*c^5*d^7*e^2 + 22*a*c^4*d^5*e^4 - 4*a^2*c^3* d^3*e^6)*x^3 + 6*(462*c^5*d^8*e + 99*a*c^4*d^6*e^3 - 44*a^2*c^3*d^4*e^5 + 8*a^3*c^2*d^2*e^7)*x^2 + (1155*c^5*d^9 + 924*a*c^4*d^7*e^2 - 792*a^2*c^3*d ^5*e^4 + 352*a^3*c^2*d^3*e^6 - 64*a^4*c*d*e^8)*x)*sqrt(c*d*e*x^2 + a*d*e + (c*d^2 + a*e^2)*x)*sqrt(e*x + d)/(c^5*d^5*e*x + c^5*d^6)
Timed out. \[ \int (d+e x)^{7/2} \sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2} \, dx=\text {Timed out} \]
Time = 0.22 (sec) , antiderivative size = 296, normalized size of antiderivative = 1.00 \[ \int (d+e x)^{7/2} \sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2} \, dx=\frac {2 \, {\left (315 \, c^{5} d^{5} e^{4} x^{5} + 1155 \, a c^{4} d^{8} e - 1848 \, a^{2} c^{3} d^{6} e^{3} + 1584 \, a^{3} c^{2} d^{4} e^{5} - 704 \, a^{4} c d^{2} e^{7} + 128 \, a^{5} e^{9} + 35 \, {\left (44 \, c^{5} d^{6} e^{3} + a c^{4} d^{4} e^{5}\right )} x^{4} + 10 \, {\left (297 \, c^{5} d^{7} e^{2} + 22 \, a c^{4} d^{5} e^{4} - 4 \, a^{2} c^{3} d^{3} e^{6}\right )} x^{3} + 6 \, {\left (462 \, c^{5} d^{8} e + 99 \, a c^{4} d^{6} e^{3} - 44 \, a^{2} c^{3} d^{4} e^{5} + 8 \, a^{3} c^{2} d^{2} e^{7}\right )} x^{2} + {\left (1155 \, c^{5} d^{9} + 924 \, a c^{4} d^{7} e^{2} - 792 \, a^{2} c^{3} d^{5} e^{4} + 352 \, a^{3} c^{2} d^{3} e^{6} - 64 \, a^{4} c d e^{8}\right )} x\right )} \sqrt {c d x + a e} {\left (e x + d\right )}}{3465 \, {\left (c^{5} d^{5} e x + c^{5} d^{6}\right )}} \]
2/3465*(315*c^5*d^5*e^4*x^5 + 1155*a*c^4*d^8*e - 1848*a^2*c^3*d^6*e^3 + 15 84*a^3*c^2*d^4*e^5 - 704*a^4*c*d^2*e^7 + 128*a^5*e^9 + 35*(44*c^5*d^6*e^3 + a*c^4*d^4*e^5)*x^4 + 10*(297*c^5*d^7*e^2 + 22*a*c^4*d^5*e^4 - 4*a^2*c^3* d^3*e^6)*x^3 + 6*(462*c^5*d^8*e + 99*a*c^4*d^6*e^3 - 44*a^2*c^3*d^4*e^5 + 8*a^3*c^2*d^2*e^7)*x^2 + (1155*c^5*d^9 + 924*a*c^4*d^7*e^2 - 792*a^2*c^3*d ^5*e^4 + 352*a^3*c^2*d^3*e^6 - 64*a^4*c*d*e^8)*x)*sqrt(c*d*x + a*e)*(e*x + d)/(c^5*d^5*e*x + c^5*d^6)
Leaf count of result is larger than twice the leaf count of optimal. 1092 vs. \(2 (265) = 530\).
Time = 0.32 (sec) , antiderivative size = 1092, normalized size of antiderivative = 3.70 \[ \int (d+e x)^{7/2} \sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2} \, dx=\frac {2 \, {\left (\frac {1155 \, d^{4} {\left (\frac {\sqrt {-c d^{2} e + a e^{3}} c d^{2} - \sqrt {-c d^{2} e + a e^{3}} a e^{2}}{c d} + \frac {{\left ({\left (e x + d\right )} c d e - c d^{2} e + a e^{3}\right )}^{\frac {3}{2}}}{c d e}\right )} {\left | e \right |}}{e^{2}} + 198 \, d^{2} {\left (\frac {15 \, \sqrt {-c d^{2} e + a e^{3}} c^{3} d^{6} - 3 \, \sqrt {-c d^{2} e + a e^{3}} a c^{2} d^{4} e^{2} - 4 \, \sqrt {-c d^{2} e + a e^{3}} a^{2} c d^{2} e^{4} - 8 \, \sqrt {-c d^{2} e + a e^{3}} a^{3} e^{6}}{c^{3} d^{3} e^{2}} + \frac {35 \, {\left ({\left (e x + d\right )} c d e - c d^{2} e + a e^{3}\right )}^{\frac {3}{2}} a^{2} e^{6} - 42 \, {\left ({\left (e x + d\right )} c d e - c d^{2} e + a e^{3}\right )}^{\frac {5}{2}} a e^{3} + 15 \, {\left ({\left (e x + d\right )} c d e - c d^{2} e + a e^{3}\right )}^{\frac {7}{2}}}{c^{3} d^{3} e^{5}}\right )} {\left | e \right |} - 44 \, d e {\left (\frac {35 \, \sqrt {-c d^{2} e + a e^{3}} c^{4} d^{8} - 5 \, \sqrt {-c d^{2} e + a e^{3}} a c^{3} d^{6} e^{2} - 6 \, \sqrt {-c d^{2} e + a e^{3}} a^{2} c^{2} d^{4} e^{4} - 8 \, \sqrt {-c d^{2} e + a e^{3}} a^{3} c d^{2} e^{6} - 16 \, \sqrt {-c d^{2} e + a e^{3}} a^{4} e^{8}}{c^{4} d^{4} e^{3}} + \frac {105 \, {\left ({\left (e x + d\right )} c d e - c d^{2} e + a e^{3}\right )}^{\frac {3}{2}} a^{3} e^{9} - 189 \, {\left ({\left (e x + d\right )} c d e - c d^{2} e + a e^{3}\right )}^{\frac {5}{2}} a^{2} e^{6} + 135 \, {\left ({\left (e x + d\right )} c d e - c d^{2} e + a e^{3}\right )}^{\frac {7}{2}} a e^{3} - 35 \, {\left ({\left (e x + d\right )} c d e - c d^{2} e + a e^{3}\right )}^{\frac {9}{2}}}{c^{4} d^{4} e^{7}}\right )} {\left | e \right |} + e^{2} {\left (\frac {315 \, \sqrt {-c d^{2} e + a e^{3}} c^{5} d^{10} - 35 \, \sqrt {-c d^{2} e + a e^{3}} a c^{4} d^{8} e^{2} - 40 \, \sqrt {-c d^{2} e + a e^{3}} a^{2} c^{3} d^{6} e^{4} - 48 \, \sqrt {-c d^{2} e + a e^{3}} a^{3} c^{2} d^{4} e^{6} - 64 \, \sqrt {-c d^{2} e + a e^{3}} a^{4} c d^{2} e^{8} - 128 \, \sqrt {-c d^{2} e + a e^{3}} a^{5} e^{10}}{c^{5} d^{5} e^{4}} + \frac {1155 \, {\left ({\left (e x + d\right )} c d e - c d^{2} e + a e^{3}\right )}^{\frac {3}{2}} a^{4} e^{12} - 2772 \, {\left ({\left (e x + d\right )} c d e - c d^{2} e + a e^{3}\right )}^{\frac {5}{2}} a^{3} e^{9} + 2970 \, {\left ({\left (e x + d\right )} c d e - c d^{2} e + a e^{3}\right )}^{\frac {7}{2}} a^{2} e^{6} - 1540 \, {\left ({\left (e x + d\right )} c d e - c d^{2} e + a e^{3}\right )}^{\frac {9}{2}} a e^{3} + 315 \, {\left ({\left (e x + d\right )} c d e - c d^{2} e + a e^{3}\right )}^{\frac {11}{2}}}{c^{5} d^{5} e^{9}}\right )} {\left | e \right |} - \frac {924 \, d^{3} {\left (\frac {3 \, \sqrt {-c d^{2} e + a e^{3}} c^{2} d^{4} - \sqrt {-c d^{2} e + a e^{3}} a c d^{2} e^{2} - 2 \, \sqrt {-c d^{2} e + a e^{3}} a^{2} e^{4}}{c^{2} d^{2}} + \frac {5 \, {\left ({\left (e x + d\right )} c d e - c d^{2} e + a e^{3}\right )}^{\frac {3}{2}} a e^{3} - 3 \, {\left ({\left (e x + d\right )} c d e - c d^{2} e + a e^{3}\right )}^{\frac {5}{2}}}{c^{2} d^{2} e^{2}}\right )} {\left | e \right |}}{e^{2}}\right )}}{3465 \, e} \]
2/3465*(1155*d^4*((sqrt(-c*d^2*e + a*e^3)*c*d^2 - sqrt(-c*d^2*e + a*e^3)*a *e^2)/(c*d) + ((e*x + d)*c*d*e - c*d^2*e + a*e^3)^(3/2)/(c*d*e))*abs(e)/e^ 2 + 198*d^2*((15*sqrt(-c*d^2*e + a*e^3)*c^3*d^6 - 3*sqrt(-c*d^2*e + a*e^3) *a*c^2*d^4*e^2 - 4*sqrt(-c*d^2*e + a*e^3)*a^2*c*d^2*e^4 - 8*sqrt(-c*d^2*e + a*e^3)*a^3*e^6)/(c^3*d^3*e^2) + (35*((e*x + d)*c*d*e - c*d^2*e + a*e^3)^ (3/2)*a^2*e^6 - 42*((e*x + d)*c*d*e - c*d^2*e + a*e^3)^(5/2)*a*e^3 + 15*(( e*x + d)*c*d*e - c*d^2*e + a*e^3)^(7/2))/(c^3*d^3*e^5))*abs(e) - 44*d*e*(( 35*sqrt(-c*d^2*e + a*e^3)*c^4*d^8 - 5*sqrt(-c*d^2*e + a*e^3)*a*c^3*d^6*e^2 - 6*sqrt(-c*d^2*e + a*e^3)*a^2*c^2*d^4*e^4 - 8*sqrt(-c*d^2*e + a*e^3)*a^3 *c*d^2*e^6 - 16*sqrt(-c*d^2*e + a*e^3)*a^4*e^8)/(c^4*d^4*e^3) + (105*((e*x + d)*c*d*e - c*d^2*e + a*e^3)^(3/2)*a^3*e^9 - 189*((e*x + d)*c*d*e - c*d^ 2*e + a*e^3)^(5/2)*a^2*e^6 + 135*((e*x + d)*c*d*e - c*d^2*e + a*e^3)^(7/2) *a*e^3 - 35*((e*x + d)*c*d*e - c*d^2*e + a*e^3)^(9/2))/(c^4*d^4*e^7))*abs( e) + e^2*((315*sqrt(-c*d^2*e + a*e^3)*c^5*d^10 - 35*sqrt(-c*d^2*e + a*e^3) *a*c^4*d^8*e^2 - 40*sqrt(-c*d^2*e + a*e^3)*a^2*c^3*d^6*e^4 - 48*sqrt(-c*d^ 2*e + a*e^3)*a^3*c^2*d^4*e^6 - 64*sqrt(-c*d^2*e + a*e^3)*a^4*c*d^2*e^8 - 1 28*sqrt(-c*d^2*e + a*e^3)*a^5*e^10)/(c^5*d^5*e^4) + (1155*((e*x + d)*c*d*e - c*d^2*e + a*e^3)^(3/2)*a^4*e^12 - 2772*((e*x + d)*c*d*e - c*d^2*e + a*e ^3)^(5/2)*a^3*e^9 + 2970*((e*x + d)*c*d*e - c*d^2*e + a*e^3)^(7/2)*a^2*e^6 - 1540*((e*x + d)*c*d*e - c*d^2*e + a*e^3)^(9/2)*a*e^3 + 315*((e*x + d...
Time = 10.59 (sec) , antiderivative size = 346, normalized size of antiderivative = 1.17 \[ \int (d+e x)^{7/2} \sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2} \, dx=\frac {\sqrt {c\,d\,e\,x^2+\left (c\,d^2+a\,e^2\right )\,x+a\,d\,e}\,\left (\frac {2\,e^3\,x^5\,\sqrt {d+e\,x}}{11}+\frac {4\,x^2\,\sqrt {d+e\,x}\,\left (8\,a^3\,e^6-44\,a^2\,c\,d^2\,e^4+99\,a\,c^2\,d^4\,e^2+462\,c^3\,d^6\right )}{1155\,c^3\,d^3}+\frac {\sqrt {d+e\,x}\,\left (256\,a^5\,e^9-1408\,a^4\,c\,d^2\,e^7+3168\,a^3\,c^2\,d^4\,e^5-3696\,a^2\,c^3\,d^6\,e^3+2310\,a\,c^4\,d^8\,e\right )}{3465\,c^5\,d^5\,e}+\frac {2\,e^2\,x^4\,\left (44\,c\,d^2+a\,e^2\right )\,\sqrt {d+e\,x}}{99\,c\,d}+\frac {x\,\sqrt {d+e\,x}\,\left (-128\,a^4\,c\,d\,e^8+704\,a^3\,c^2\,d^3\,e^6-1584\,a^2\,c^3\,d^5\,e^4+1848\,a\,c^4\,d^7\,e^2+2310\,c^5\,d^9\right )}{3465\,c^5\,d^5\,e}+\frac {4\,e\,x^3\,\sqrt {d+e\,x}\,\left (-4\,a^2\,e^4+22\,a\,c\,d^2\,e^2+297\,c^2\,d^4\right )}{693\,c^2\,d^2}\right )}{x+\frac {d}{e}} \]
((x*(a*e^2 + c*d^2) + a*d*e + c*d*e*x^2)^(1/2)*((2*e^3*x^5*(d + e*x)^(1/2) )/11 + (4*x^2*(d + e*x)^(1/2)*(8*a^3*e^6 + 462*c^3*d^6 + 99*a*c^2*d^4*e^2 - 44*a^2*c*d^2*e^4))/(1155*c^3*d^3) + ((d + e*x)^(1/2)*(256*a^5*e^9 - 1408 *a^4*c*d^2*e^7 - 3696*a^2*c^3*d^6*e^3 + 3168*a^3*c^2*d^4*e^5 + 2310*a*c^4* d^8*e))/(3465*c^5*d^5*e) + (2*e^2*x^4*(a*e^2 + 44*c*d^2)*(d + e*x)^(1/2))/ (99*c*d) + (x*(d + e*x)^(1/2)*(2310*c^5*d^9 + 1848*a*c^4*d^7*e^2 - 1584*a^ 2*c^3*d^5*e^4 + 704*a^3*c^2*d^3*e^6 - 128*a^4*c*d*e^8))/(3465*c^5*d^5*e) + (4*e*x^3*(d + e*x)^(1/2)*(297*c^2*d^4 - 4*a^2*e^4 + 22*a*c*d^2*e^2))/(693 *c^2*d^2)))/(x + d/e)